⚡ Bolt: O(N log N) 정렬 대신 O(N) 탐색 사용 - #225
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No actionable comments were generated in the recent review. 🎉 ℹ️ Recent review info⚙️ Run configurationConfiguration used: Organization UI Review profile: CHILL Plan: Pro Plus Run ID: 📒 Files selected for processing (3)
📝 WalkthroughWalkthroughp-value 후보 선택을 Changes탐색 최적화 및 지원 변경
Estimated code review effort: 2 (Simple) | ~10 minutes 🚥 Pre-merge checks | ✅ 5✅ Passed checks (5 passed)
✨ Finishing Touches🧪 Generate unit tests (beta)
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Closing as superseded by #178. Both replace the full |
Understood. Acknowledging that this work is now obsolete and stopping work on this task. |
💡 What:
surveyFA.R에서 최솟값을 찾을 때 사용하던names(sort(x))[1L]패턴을names(x)[which.min(x)]로 변경했습니다.🎯 Why:
sort(x)를 호출하면 전체 배열을 정렬해야 하므로 O(N log N)의 시간 복잡도가 발생합니다. 최솟값 하나만 필요한 경우에는 O(N) 선형 탐색을 수행하는which.min()을 사용하는 것이 성능상 유리합니다.📊 Impact: 요소 수가 많은 배열에서 반복적으로 최솟값을 찾을 때 불필요한 정렬 오버헤드를 제거하여 성능을 향상시킵니다.
🔬 Measurement:
R/surveyFA.R파일 내에which.min(p_values)가 제대로 적용되었는지 확인하고 패키지 테스트 스위트를 실행하여 정상 동작함을 확인했습니다.PR created automatically by Jules for task 2967854970973391237 started by @seonghobae
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