Manchester | 26-ITP-May | Yee Man Tsang | Sprint 3 | 2-practice-tdd by lintsang · Pull Request #1507 · CodeYourFuture/Module-Structuring-and-Testing-Data

lintsang · 2026-07-13T18:42:37Z

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Changelist

Finished all exercises in 2-practice-tdd folder

Liam310 · 2026-07-14T11:21:34Z

Don't forget to add the Needs review label to your coursework Lin otherwise it might get missed by reviewers!

(I've picked this up today but bear it in mind for future!)

Liam310 · 2026-07-14T11:41:59Z

+  if (String(num).length > 1) {
+    //check if the number has more than 1 digit
+    onesDigit = Number(String(num).slice(-1)); //extract the figure at the tens digit, and convert it into a number.
+    const tensDigit = Number(String(num).slice(-2, -1)); //extract the figure at the tens digit, and convert it into a number.
+
+    if (onesDigit == 1) {
+      if (tensDigit == 1) {
+        return num + "th";
+      } else {
+        return num + "st";
+      }
+    } else if (onesDigit == 2) {
+      if (tensDigit == 1) {
+        return num + "th";
+      }
+      return num + "nd";
+    } else if (onesDigit == 3) {
+      if (tensDigit == 1) {
+        return num + "th";
+      }
+      return num + "rd";
+    } else {
+      ("th");
+    }
+  } else if (String(num).length == 1) {
+    onesDigit = Number(String(num)[0]); //extract the figure at the tens digit, and convert it into a number.
+    if (onesDigit == 1) {
+      return num + "st";
+      console.log("Yeah youre in");
+    } else if (onesDigit == 2) {
+      return num + "nd";
+    } else if (onesDigit == 3) {
+      return num + "rd";
+    } else {
+      return num + "th";
+    }
+  }


This is a mostly working solution, but with a lot of nested if statements it can be quite hard to follow the logic of it.

A few things to consider:

You repeat the same if (tensDigit == 1) { return num + "th" } line, which suggests if the tens digit of the number is 1, you're always doing the same thing. How you might you simplify this so you only need to perform that check once?

On line 25 you have an else statement that doesn't contain any logic. What should that statement be doing? Why wasn't it caught by the tests?

The logic you have for numbers whose "length" is 1 is very similar to the logic you have for numbers whose "length" is more than 1. You could definitely make this less repetitive!

In a lot of places you have used == instead of === - I asked you in a previous submission what the difference was and what would be better - same question applies here!

You've got a leftover console.log on line 32 - get rid!

Thanks for guiding me on this problem. I am having some insights for how to make this kind of statement in the future.

This is so much better Lin! I hope you are happy with this improvement 😄

Liam310 · 2026-07-28T08:29:37Z

@lintsang Really nice improvements here Lin - I have no further comments so happy to mark as Complete ✅

2-practice-tdd exercise

154190c

Liam310 added the Review in progress This review is currently being reviewed. This label will be replaced by "Reviewed" soon. label Jul 14, 2026