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Copy pathReverseOnlyLetters.java
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70 lines (63 loc) · 2.08 KB
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/**
* <p>给定一个字符串 <code>S</code>,返回 “反转后的” 字符串,其中不是字母的字符都保留在原地,而所有字母的位置发生反转。</p>
*
* <p> </p>
*
* <ol>
* </ol>
*
* <p><strong>示例 1:</strong></p>
*
* <pre><strong>输入:</strong>"ab-cd"
* <strong>输出:</strong>"dc-ba"
* </pre>
*
* <p><strong>示例 2:</strong></p>
*
* <pre><strong>输入:</strong>"a-bC-dEf-ghIj"
* <strong>输出:</strong>"j-Ih-gfE-dCba"
* </pre>
*
* <p><strong>示例 3:</strong></p>
*
* <pre><strong>输入:</strong>"Test1ng-Leet=code-Q!"
* <strong>输出:</strong>"Qedo1ct-eeLg=ntse-T!"
* </pre>
*
* <p> </p>
*
* <p><strong>提示:</strong></p>
*
* <ol>
* <li><code>S.length <= 100</code></li>
* <li><code>33 <= S[i].ASCIIcode <= 122</code> </li>
* <li><code>S</code> 中不包含 <code>\</code> or <code>"</code></li>
* </ol>
* <div><div>Related Topics</div><div><li>双指针</li><li>字符串</li></div></div><br><div><li>👍 98</li><li>👎 0</li></div>
*/
package leetcode9;
public class ReverseOnlyLetters {
public static void main(String[] args) {
Solution solution = new ReverseOnlyLetters().new Solution();
}
class Solution {
public String reverseOnlyLetters(String s) {
char[] arr = s.toCharArray();
for (int left = 0, right = arr.length - 1; left < right; left++, right--) {
while (left < right && !valid(arr, left)) left++;
while (left < right && !valid(arr, right)) right--;
if (left < right) swap(arr, left, right);
}
return new String(arr);
}
private void swap(char[] arr, int i, int j) {
char temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
private boolean valid(char[] arr, int i) {
return (arr[i] >= 'a' && arr[i] <= 'z')
|| (arr[i] >= 'A' && arr[i] <= 'Z');
}
}
}