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/**
* <p>设计一个支持 <code>push</code> ,<code>pop</code> ,<code>top</code> 操作,并能在常数时间内检索到最小元素的栈。</p>
*
* <ul>
* <li><code>push(x)</code> —— 将元素 x 推入栈中。</li>
* <li><code>pop()</code> —— 删除栈顶的元素。</li>
* <li><code>top()</code> —— 获取栈顶元素。</li>
* <li><code>getMin()</code> —— 检索栈中的最小元素。</li>
* </ul>
*
* <p> </p>
*
* <p><strong>示例:</strong></p>
*
* <pre><strong>输入:</strong>
* ["MinStack","push","push","push","getMin","pop","top","getMin"]
* [[],[-2],[0],[-3],[],[],[],[]]
*
* <strong>输出:</strong>
* [null,null,null,null,-3,null,0,-2]
*
* <strong>解释:</strong>
* MinStack minStack = new MinStack();
* minStack.push(-2);
* minStack.push(0);
* minStack.push(-3);
* minStack.getMin(); --> 返回 -3.
* minStack.pop();
* minStack.top(); --> 返回 0.
* minStack.getMin(); --> 返回 -2.
* </pre>
*
* <p> </p>
*
* <p><strong>提示:</strong></p>
*
* <ul>
* <li><code>pop</code>、<code>top</code> 和 <code>getMin</code> 操作总是在 <strong>非空栈</strong> 上调用。</li>
* </ul>
* <div><div>Related Topics</div><div><li>栈</li><li>设计</li></div></div><br><div><li>👍 1081</li><li>👎 0</li></div>
*/
package leetcode1;
import java.util.ArrayDeque;
public class MinStack1 {
public static void main(String[] args) {
}
class MinStack {
private ArrayDeque<Integer> stack = new ArrayDeque<>();
private ArrayDeque<Integer> min = new ArrayDeque<>();
public MinStack() {
}
public void push(int val) {
stack.push(val);
if (min.isEmpty() || min.peek() >= val) {
min.push(val);
}
}
public void pop() {
if (!stack.isEmpty() && stack.pop().equals(min.peek())) {
min.pop();
}
}
public int top() {
return stack.peek();
}
public int getMin() {
return min.peek();
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(val);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
}