I was recently confused that those statements are not equivalent:
graph = @StenoGraph begin
a ↔ fixed(1)*b
end
which yields
a ↔ b * Fixed{Tuple{Int64}}((1,))
graph = @StenoGraph begin
fixed(1)*b ↔ a
end
which yields
b ↔ a
I think the documentation needs to be expanded to explain how exactly the fixed() modifier is supposed to be used.
I was recently confused that those statements are not equivalent:
which yields
a ↔ b * Fixed{Tuple{Int64}}((1,))which yields
b ↔ a
I think the documentation needs to be expanded to explain how exactly the fixed() modifier is supposed to be used.