Implement ls command functionality in Python

Author: mervereis

implement-shell-tools/ls/ls.py

@@ -0,0 +1,57 @@
+import argparse
+import os
+
+parser = argparse.ArgumentParser(
+    prog="check-for-ls",
+    description="Implement my own version of ls",
+)
+
+parser.add_argument(
+    "paths",
+    nargs="*",
+    help="The file paths to process"
+)
+
+parser.add_argument(
+    "-1",
+    "--one",
+    action="store_true",
+    help="List one file per line"
+)
+
+parser.add_argument(
+    "-a",
+    action="store_true",
+    help="Show all files"
+)
+
+args = parser.parse_args()
+
+paths = args.paths
+
+if len(paths) == 0:
+    paths = ["."]
+
+for target in paths:
+
+    if os.path.isdir(target):
+        show_files = os.listdir(target)
+
+        if args.a:
+            show_files = [".", "..", *show_files]
+        else:
+            show_files = [
+                name for name in show_files
+                if not name.startswith(".")
+            ]
+
+        show_files.sort()
+
+    else:
+        show_files = [target]
+
+    if args.one:
+        for file in show_files:
+            print(file)
+    else:
+        print("  ".join(show_files))